Carla and Jonah are working together to determine if quadrilateral CDEF with coordinates C(2, 3), D(1, 2), E(4, 1), and F(5, 3) has a right angle. Carla sets up the following equations: slope of segment CD equals 2 minus 3 all over 1 minus 2 slope of segment DE equals 1 minus 2 all over 4 minus 1
Jonah sets up the following equations: slope of segment CD equals 2 minus 3 all over 1 minus 2 slope of segment EF equals 3 minus 1 all over 5 minus 4 Who is on track to get the correct answer and why?

A.)Carla is on the right track because she is finding the slopes of the opposite sides to check for right angles.
B.)Carla is on the right track because she is finding the slopes of consecutive sides to check for right angles.
C.)Jonah is on the right track because he is finding the slopes of the opposite sides to check for right angles.
D.)Jonah is on the right track because he is finding the slopes of consecutive sides to check for right angles.

B

Step-by-step explanation:

find the slope : Carla is on the right track because she is trying to find the slope of two consecutive line to find right angle( it is the second choice)

B.)Carla is on the right track because she is finding the slopes of consecutive sides to check for right angles.

Step-by-step explanation:

I took the test and got it correct.

-362

step-by-step explanation:

(12)(4)+2(12)-34(12)+2(12)-3

  \/         \/         \/         \/

  48 +   24 -   408 + 24 - 3

      \   /               \   /

          72     -     432 - 3 = -363

the answer is: d) o, f, and kr.

atomic radius of bromine (br) is 114 pm.

atomic radius of oxygen (o) is 73 pm.

atomic radius of fluorine (f) is 72 pm.

atomic radius of krypron (kr) is 112 pm.

the atomic radius of a chemical element is a measure of the size of its atom.

the atomic radius varies with increasing atomic number, but usually increases because of increasing of number of electrons.

the atomic radius decreases across the periods because an increasing number of protons, because greater attraction between the protons and electrons.