Tony used a photocopier to dilate the design for a monorail track system. The figure below shows the design and its photocopy: Two irregular quadrilaterals ABCD and EFGH are drawn. EFGH is the photocopy of design ABCD. AD measures 8 meters, AB measures 1 The ratio of CD:GH is 2:3. What is the length, in meters, of side EH on the photocopied image? (5 points) GIVE A FULL ANSWER NOT JUST "BECAUSE IT IS"

12 meters.

Step-by-step explanation:

Since the ratio of CD : GH is 2 : 3, we can assume that the ratio of quadrilaterals ABCD : EFGH is also 2 : 3.

According to the diagram, segment AD corresponds to segment EH. You can then set up a proportion to calculate the length of side EH...

To make the proportion, I did the ratio of AD over the length equals the ratio of EH over the length, x.

=

That would lead to 2x = 3 * 8

2x = 24

x = 12

So, the length, in meters, of side EH on the photocopied image (5 points) is 12 meters.

I hope this was a full answer, because it is, and I hope this helps!

the equation cos(35) =a/25 can be used to find the length of bc what is the length of bc? round to the nearest tenth

step-by-step explanation:

the graph in the attached figure

step-by-step explanation:

we have

using a graphing tool

the graph in the attached figure

the roots are ( x-intercepts) x=-0.5,x=1,x=3

the y-intercept is the point (0,3)