A playing field has length(2n+5)m and width (n+1)m if perimeter is 360 m find value of n

58

Step-by-step explanation:

Assuming the playing field is a rectangle.

Perimeter = 2l + 2w

2(2n+5) + 2(n + 1) = 360

4n + 10 + 2n + 2 = 360

6n + 12 = 360

6n = 348

n = 348/6

n = 58

The value of n is 58.

a. the are of the rectangle is 18.25

b. 18.25 times two is 36.50

rae me : d

y > 1/3x

y < = -x + 4

hope this : )