A political scientist wants to prove that a candidate is currently carrying more than 60% of the vote in the state. She has her assistants randomly sample 200 eligible voters in the state by telephone and only 90 declare that they support her candidate. The observed z value for this problem is . 4.33 2.33 0.45 -.31 -4.33

Z= -4.33

Step-by-step explanation:

Hello!

The study variable is:

X: number of voters that support the candidate out of 200 surveyed voters.

This variable has a binomial distribution, where the "success" is that the voter supports the candidate and the "failure" is that the voter doesn't support the candidate. X~Bi(n;p)

Considering the sample size is large enough, you can apply the Central Limit Theorem and approximate the distribution of the sample proportion to normal: ^p ≈ N(p;)

Using this distribution you can an approximation to the standard normal distribution: ≈N(0;1)

Where the sample proportion is ^p= p'=

x= number of successes

n= sample size

The population proportion is p= 0.60

I hope this helps!

$4034.40

the perimeter of the field is the sum of the lengths of the four sides:

47 yd + 158 yd + 47 yd + 158 yd = 410 yd

the cost of 3 ft (1 yd) of fence is 3×$3.28 = $9.84.

so the cost of jake's wood perimeter fance is

(410 yd) × ($9.84 /yd) = $4034.40

thats not a system of equations, that is a solution