Given the system of linear equations. x=y+3 y=-4x-3 Part A: Solve the linear system of equations by graphing Part B: Use substitution to solve the linear system of equations Part C: Use addition to solve the linear system of equations In your final answer, include all of your work, the graph of the equations and the solution.

see below

Step-by-step explanation:

x=y+3

Subtract 3 from each side

x-3 = y

y = x-3

y=-4x-3

We have both equations in slope intercept form

y = mx +b where m is the slope and b is the y intercept

graph is below

They both have the same y intercept so they intersect at (0,-3)

Substitution

x=y+3

y=-4x-3

Substitute the second equation into the first equation

x=y+3

x = -4x-3 +3

x = -4x

Add 4x to each side

5x =0

x=0

y = -4x-3

y = 0-3

y = -3

(0,-3)

Additon

x=y+3

Subtract y from each side

x-y = 3

y=-4x-3

Add 4x to each side

4x+y =-3

Add the equations together to eliminate y

x-y = 3

4x+y =-3

-----------------

5x +0y =0

5x = 0

x=0

Now solve for y

y = -4x-3

y = 0-3

y = -3

(0,-3)

ask the math teacher she or he would know lol.

step-by-step explanation: