The length of the smaller rectangle at the right is 1 inch less than twice its width. Both the dimensions of the larger rectangle are 2 inches longer than the smaller rectangle. The area of the shaded region is 86 square inches. What is the area of the larger rectangle? PLEASE its important

 464 square inches is the area of the larger rectangle.

Step-by-step explanation:  Assuming that the shaded area is the part of the large rectangle outside the small rectangle, you can set up dimensions from the information given.

The small rectangle's Area = w (2w -1) which is 2w² -w

The large rectangle's Area = (w + 2)(2w + 1) which is 2w² + 5w +2

Now figure out the equation for the "shaded area" (probably outside the small rectangle)  2w² + 5w +2 -(2w² -w) = 86  (The 2w² terms cancel)

6w + 2 = 86,  so 6w = 84, w=14  

Substitute 14 for w in the dimensions of the large rectangle: (w + 2)(2w + 1)

(14+2)(2[14] + 1) = Area

16 × 29 = 464

(I think I deserve Brainliest for figuring this out, but I see the question has been red-flagged, so We'll see!)

360/29

step-by-step explanation:

5x + 5

step-by-step explanation:

you should always add the diagrams and graphs we cannot see. this particular question is kind of borderline because we can make a graph for you.

(f + g)x = -x^2 +3x + 5 + x^2 + 2x

(f + g)x = 5x + 5

the graph of z = 5x + 5 is shown below. always use desmos when in doubt.