The solutions of the equation x^2-6x+4=0 can be written as ± √b, where a and b are prime numbers. Solve x^2-6x+4=0 to find the values of a and b

a = 3, b = 5

Step-by-step explanation:

Given

x² - 6x + 4 = 0 ( subtract 4 from both sides )

x² - 6x = - 4

Using the method of completing the square

add ( half the coefficient of the x- term )² to both sides

x² + 2(- 3)x + 9 = - 4 + 9

(x - 3)² = 5 ( take the square root of both sides )

x - 3 = ± ( add 3 to both sides )

x = 3 ± ← in the form a ±

with a = 3 and b = 5

a complex number is a number that can be expressed in the form a + bi, where a and b are real numbers, and i is a solution of the equation x2 = −1. because no real number satisfies this equation, i is called an imaginary number. has no real solution, since the square of a real number cannot be negative.