Consider the initial value problem y' + 3y = 9t, y(0) = 7. a. Take the Laplace transform of both sides of the given differential equation to create the corresponding algebraic equation. Denote the Laplace transform of y(t) by Y(s). Do not move any terms from one side of the equation to the other (until you get to part (b) below).
b. Solve your equation for Y(s).
Y(s) = L {y(t)} =
c. Take the inverse Laplace transform of both sides of the previous equation to solve for y(t).
y(t) =

Step-by-step explanation:

Recall that the following laplace transforms

The laplace transform is linear, so, applying the laplace transform to the equation we get

By some algebraic manipulations, we get

which is equivalent to

By using the partial fraction decomposition, we get

then

Using that

by taking the inverse on both sides we get

answer;

the correct answer

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5x+40

5(x + 8)

7x - 49

7(x - 7)

18x + 9

9(2x + 1)

15x - 10

5(3x - 2)

step-by-step explanation:

for number one all you have to do is factor 5 out of 5x + 40

for number 2 factor 7 out of 7x - 49

for number three factor 9 out of 18x + 9

for number four factor 5 out of 15x - 10