Use structural induction to show that l(T), the number of leaves of a full binary tree T, is 1 more than i(T), the number of internal vertices of T, where an "internal vertex" is one with children. Which is the correct basis step? Suppose Ti and T are disjoint full binary trees
i(T) + 1
Let T + T1 + T2
T's leaves are those of Ti plus those of T2, so I(T) = I(T1) + I(T2). T's internal vertices are its root plus the internal vertices of T1 and T2, so i(T) 1(T) = i(T1) + i( T2).

depending on others is critical to survival. my source is apex!

step-by-step explanation:

answer: 33 ( approx)

step-by-step explanation:

since, in the linear regression formula, the slope is the a in the equation y = b + ax ( by comparing it with the general equation of line y = mx + c )

where,

here given table is,

price ($), x   :           18         23       25       29       30       33

pairs sold, y :         16         13         10       8         6       2

so, ,   ,   ,

and   ,

thus, slop of the given line is,

⇒  

⇒   ≈ 33