In 1985 Maria was 3 times as old as Sue. Five years earlier the sum of their ages was 18. When was Maria born?

Maria was born in 1964

Step-by-step explanation:

Let Sue's age be x

Maria's age be 3x

Five years ago, their ages were

x-5, 3x-5

So

(x-5) + (3x-5) = 18

x-5 + 3x - 5 = 18

4x -10 = 18

4x = 18+10

x = 28/4 = 7

Sue's age x-5 = 7-5 = 2

Maria's age = 3x-5 = 3(7)-5 = 21-5=16

Maria was born in 1980 - 16 = 1964

1964

Step-by-step explanation:

to solve this question we should assign an equation for each year :

let x be Maria's age and y Sue's age.

Now let's solve each equation by trying to minimise the number of variables we are dealing with

how ?

let's multiply x+y= 18  by -1

we get -x-y=-18

Now let's add this last equation to x-3y-10 = 0 to get rid of x

so Sue's age is 2 .

let's calculate x the age of Maria by replacing y by 2 in x+y= 18

Let's check : in 1985 Maria's age is 21 and sue's age is 7

so it's true.

Now let's calculate Maria's year of birth :

In 1985 Maria was 21 so :

Maria was born in 1964

step-by-step explanation:

ok one would be money, and the other would be refreshments or something similar. if each bag of popcorn is 5.00 and each drink is half of that that means drinks are 2.50 the proper way to do that would to look and see how much of each you can buy without exceeding a limit of 30.00

900 degrees

step-by-step explanation: