a)express x^2+12x+11 in the form (x+p)^2+q b)A curve has equation y=x^2+12x+11. What are the co-ordinates of the turning point of the curve

a) (x+6)^2-25

b) (-6, -25)

Step-by-step explanation:

Perfect square trinomial! If you have 12x, divide by two and get 6, so we have (x+6)^2+q. Then solve for q. You get q as -25.

For b, we just take the vertex from vertex form. We get x+6=0 so x=-6, and q = -25, so the answer is (-6, -25).

Hope that helped,

-sirswagger21

the value of v.w= -12.

step-by-step explanation:

we are given three vector r,v and w as:

r = < 5, -5, -2> ; v = < 2, -8, -8> ; w = < -2, 6, -5>

we know that r,v and w could also be represented as:

r=5i-5j-2k

v=2i-8j-8k

and w= -2i+6j-5k

where i,j and k are the unit vectors of x,y and z-axis respectively.

also we know that it has the following property:

i.i=1 ; j.j=1; k.k=1

and i.=j.i=i.k=k.i=j.k=k.j=0

i.e. when we multiply two vectors or we find it's dot product we need to only multiply the components of x coordinates with each other; y with each other and z with each other.

hence, v.w= (2i-8j- -2i+6j-5k)

                  = 2×(-2)+(-8)×(6)+(-8)×(-5)

                  = -4-48+40

                  = -12

hence, v.w= -12

what graph

step-by-step explanation: