If p(x) = x2 - 1 and 4(x) = 5(x-1), which expression is equivalent to (p - 9)(x)? 5(x - 1) - x2-1
(5x-1) -(x2-1)
(x2 - 1) - 5(x - 1)
(x2-1) - 5x-1

x^2 - 10 = (p - 9)(x)

Step-by-step explanation:

Please indicate exponentiation with the symbol " ^ ":  p(x) = x^2 - 1.

To obtain (p - 9), start with p(x) = x^2 - 1 and subtract 9:

(p - 9)(x) = x^2 - 1 - 9 = x^2 - 10 = (p - 9)(x)

so far i think you have the right thing going for you just remember soh cah toh

step-by-step explanation:

sine over hypotenuse

cosine   equals adjacent

tangent over hypotenuse

step-by-step explanation: