Mario and Tabitha are calculating the probability of getting a 4 and a 2 if they roll a die twice. Who is correct? Explain your reasoning.

1/6 × 1/6

The complete question related to this as found on math24seven website is stated below:

Find the errors. Mario and Tabitha are calculating the probability of getting a 4 and then a 2 if they roll a die twice. Who is correct? Explain your reasoning.

Find attached their calculations

Step-by-step explanation:

We are to determine which of the two calculations given by Mario and Tabitha for getting a probability of 4 and then 2  is correct.

To do this, let's work out the calculations ourselves.

In a die, we have the faces numbered from 1 to 6

Outcome of rolling a die = {1, 2, 3, 4, 5, 6}

If the die is rolled twice, the probability of getting a 4 and then 2 = Pr(4 in the first roll and 2 in the 2nd roll)

Let the probability = Pr(2 and 4)

Probability of getting 2 = Pr(2)

Pr(2) = (number times it occurred)/(total number of outcome)

Pr(2) = 1/6

Probability of getting 4 = Pr(4)

Pr(4) = (number times it occurred)/(total number of outcome)

Pr(4) = 1/6

Pr(2 and 4) = 1/6 × 1/6

Looking at both calculations, only Mario has same answer as derived from the calculation.

Therefore Mario is correct.

answer: (c) m∠qpo + (2x + 16)° = 180°

step-by-step explanation:

the opposite angles of a quadrilateral are supplementary.

so, ∠o + ∠q = 180°   and   ∠p + ∠r = 180°

since ∠r = 2x + 16°, we can use substitution as follows:

∠p + ∠r = 180°

∠p + (2x + 16)° = 180°

d

step-by-step explanation: