I WILL GIVE BRAINLIEST. Please help! Given the equation A=250(1.1)^t, you can determine that the interest is compounded annually and the interest rate is 10%. Suppose the interest rate were to change to being compounded quarterly. Rewrite the equation to find the new interest rate that would keep A and P the same. What is the approximate new interest rate?
Convert your answer to a percentage, round it to the nearest tenth, and enter it in the space provided, like this: 42.53%

2.5%

Step-by-step explanation:

Hi, to answer this question we have to apply the compounded interest formula:  

A = P (1 + r/n) nt  

Where:  

A = Future value of investment (principal + interest)  

P = Principal Amount  

r = Nominal Interest Rate (decimal form, 10/100= 0.1)  

n= number of compounding periods in each year (365)  

Replacing with the values given  

A=250(1+0.1/1)^t/1

A=250(1.1)^t

For a interest compounded annually, n=1, compounded quarterly n= 4 (4quarters in a year )

Interest rate 0.1 /4 = 0.025= 2.5%

hello from mrbilldoesmath!

answer:   x^2 + y^2 = 1024

discussion:

the equation of a circle with center (h,k) and radius "r" is

(x-h)^2 + (y-k)^2 = r^2.

in our case

(x-0)^2 + (y-0) ^2 = 32^2 = 1024

you,

mrb

yeah i know the problem you need. i am taking it right now. the answer is step 3

~mickey