SOMEONE HELP PLEASE!! Will make as brainleist!??

This is a geometric sequence and the common ratio is equal to ½.

Step-by-step explanation:

For a sequence to be termed to be in arithmetic progression, the difference between consecutive terms are the same and constant.

On the other hand, a sequence is termed to be in geometric progression if the ratio of a term to the term before it is the same as the ratio between the next term to it.

Let's consider the sequence given: 12, 6, 3 . . .

=>Let's try to find the common difference if it would be constant: 6-12 (-6) ≠ 3-6 (-3)

The sequence is not arithmetic.

=>Let's also try to find the ratio of the sequence to see if it is constant:

6/12 (½) = 3/6 (½)

Therefore we can conclude the sequence is geometric because the common ratio (½) is constant.

This is a geometric sequence and the common ratio is equal to ½.

place r′ so that qr′ is parallel to the tangent.

now we get that ∠r′py=∠pr′q, where y is on the tangent, on the opposite side of p from x.

also, because of the symmetry, ∠r′py=∠qpx.

finally, note that no matter where we place r, as long as it's on the correct arc, we have ∠prq=∠pr′q.

stringing all these equalities together, we end up with ∠prq=∠qpx.

this picture will show how its going to look like.

hope this by jack monhen

hello!

some people may think so but i don't. its just a human instinct in my opinion.

have a fantastic day! ~pooch ♥