According to the U. S. Department of Agriculture, Alabama egg farmers produce millions of eggs every year. Suppose egg production per year in Alabama is normally distributed, with a standard deviation of 83 million eggs. If during only 3% of the years Alabama egg farmers produce more than 2,655 million eggs, what is the mean egg production by Alabama farmers?

The mean egg production 2499 million

Step-by-step explanation:

P(Z > a) = 3% = 0.03

P(Z > a) = 1 - ∅(a)

1 - ∅(a) = 0.03

∅(a) = 1 - 0.03

∅(a) = 0.97

Checking the normal distribution curve, for ∅(a) = 0.97, z = 1.88

This means that area under the normal curve is 3% (0.03) to the right of z = 1.8808

X = μ + (zб)

X = 2,655 millions

б = 83 million

2655 =  μ + (1.88 * 83)

2655 =  μ + 156.04

μ  = 2655 - 156.04

μ = 2498.96

The mean egg production, is therefore, 2499 million

t= half of the arc subtended by t.

r= half of the arc subtended by r.  

t+r= half of the arc subtended by t + half of the arc subtended by r= half of 360=180

step-by-step explanation: