Please find x: x−5=11−3x

x−5=11−3x

Group all the constants at one side

That's

x + 3x =11 + 5

4x = 16

Divide both sides by 4

4x/4 = 16/4

x = 4

Hope this helps you

x=4

Step-by-step explanation:

x−5=11−3x

take care of all the variables

you want to put the variables on one side and the numbers on the other

x−5=11−3x

+3x     +3x

4x-5=11

+5    +5

4x=16

÷4  ÷4

x=4

hope this helps :)

solution:

the given function is ,

      =

the three roots of this quadratic function is , 0 ,8 and 10.all the roots are real and rational.

if a quadratic equation is of the form ,

sum of the roots = a + b +c= 0+8+10=18=  

product of roots taken two at a time = a b + b c+ c a = 0+80+0=80 =  

product of roots = a b c = 0=  

there are 11 doors in a hall starting from 0 to 11.the entry in the hall is permitted through gate number 0 and exit is allowed through only gate number 8 and 10.so, three roots(0,8,10) of quadratic function is given by entry and exit route of this hall.