A girl walks 800 m on a bearing of 129°. Calculate how far: a east b south she is from
her starting point.

a) 503.2m

b) 621.6m

Step-by-step explanation:

The diagram representing the scenario is shown in the attached photo.

A represents her starting point.

CD = x = how far east she is from her starting point

BC = y = how far south she is from her starting point

Angle BAC = 180 - 129 = 51°

Angle ACD = angle BAC = 51° because they are alternate angles

To determine x, we would apply the cosine trigonometric ratio

Cos 51 = x /800

x = 800Cos51 = 800 × 0.629 = 503.2m

To determine y, we would apply the sine trigonometric ratio

Sin 51 = y /800

y = 800Sin51 = 800 × 0.777 = 621.6m

something over 10 so ? /10

step-by-step explanation:

hello from mrbilldoesmath!

answer:

(7 x + 6 y) (49 x^2 - 42 x y + 36 y^2)

discussion:

the trick is to recognize that 343 = 7^3 and 216 = 6^3 and, in general,

a^3 + b^3 =   (a + b) (a^2 - a b + b^2).

in our case

343x^3+216y^3   =   (7x)^3 + (6y)^3

so take a = 7x and b = 6y in the above equation to get the answer.

you,

mrb