PLS HELP AND ANSWER ASAPPP (i). A line “t” is parallel to 3y = 6x + 9. Find the slope of this line “t”. (ii) Another line “r” is perpendicular to the line 3y = 6x + 9. Find the gradient of the line “r”.

1) 2 (11) - 1/2

Step-by-step explanation:

Given the following:

A line “t” is parallel to 3y = 6x + 9

Equation of a line;

y = mx + c

Where the Coefficient of x, 'm' is the gradient or slope and c is the intercept.

From the equation;

3y = 6x + 9

Divide through by 3

y = 2x + 3

Comparing the line equation with the equation provided :

Coefficient of x = 2, therefore 2 = slope

Since line t is Parallel to y = 2x + 3

Then, slope of line 't' is the same as that of y:

Slope of line 't' = 2

(11) For perpendicular lines :

Slope of original line : 3y = 6x + 9

Divide through by 3

y = 2x + 3

Compare to line equation:

y = mx + c

m = gradient/ slope, c = intercept

Gradient of original line, m = 2

For a line 'r' perpendicular to y = 2x + 3

Gradient, m of line r equals to the negative reciprocal of the gradient of original line

Therefore, gradient of r equals :

-1/2

a is the right answer

proofs involving isosceles triangles often require special consideration because an isosceles triangle has several distinct properties that do not apply to normal triangles.(more about triangle types) therefore, when you are trying to prove that two triangles are congruent, and one or both triangles, are isosceles you have a few theorems that you can use to make your life easier.

step-by-step explanation:

an isosceles triangle has two congruent sides and two congruent angles. the congruent angles are called the base angles and the other angle is known as the vertex angle. ∠bac and ∠bca are the base angles of the triangle picture on the left. the vertex angle is ∠abc