Please can u help me Will mark brainiest

a) 3n-1

b) 2n+7

2nd image:

a) 35   method: 3×2=6²=35

b) 224     method: 3×5=15²=225

The sequence is an arithmetic sequence

For an nth term in an arithmetic sequence

U(n) = a + ( n - 1)d

Where

a is the first term

d is the common difference

n is the number of terms

a ). a = 2

d = 5 - 2 = 3

U(n) = 2 + ( n - 1)3

= 2 + 3n - 3

= 3n - 1

b.) a = 9

d = 11 - 9 = 2

U(n) = 9 + (n - 1)2

= 9 + 2n - 2

= 7 + 2n

The nth term is 3n² - 1

For the second term we get

3(2)² - 1 = 3(4) - 1 = 12 - 1 = 11

For the fifth term we get

3(5)² - 1 = 3(25) - 1

= 75 - 1

= 74

Hope this helps

1 number

if we use a graphing calculator, there is only one such number that satisfies the conclusion of the mean value theorem, that is, a number such that

where the right-hand side is the average rate of change of f on the interval [0.5,0.75], which is the slope of the secant line.

in the attached graph, the black line is the secant line which has its slope as the average rate of change of f on [0.5,0.75], while the orange line is the only tangent line to the graph of f in the interval that satisfies the mvt conclusion.

i think the answer is b