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Mathematics, 08.07.2020 19:01 brattyshae

Given: ∆ABC –iso. ∆, m∠BAC = 120° AH ⊥ BC , HD ⊥ AC
AD = a cm, HD = b cm

Find: P∆ABH


Given: ∆ABC –iso. ∆, m∠BAC = 120° AH ⊥ BC , HD ⊥ AC AD = a cm, HD = b cm Find: P∆ABH

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Given: ∆ABC –iso. ∆, m∠BAC = 120° AH ⊥ BC , HD ⊥ AC
AD = a cm, HD = b cm

Find: P∆A...
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