Suppose a polling agency reported that 44.4% of registered voters were in favor of raising income taxes to pay down the national debt. The agency states that results are based on telephone interviews with a random sample of 1049 registered voters. Suppose the agency states the margin of error for 95% confidence is 3.0%. Determine and interpret the confidence interval for the proportion of registered voters who are in favor of raising income taxes to pay down the national debt.

95% of confidence interval for the proportion of registered voters who are in favor of raising income taxes to pay down the national debt.

(0.414 ,0.474)

Step-by-step explanation:

Step(i):-

Given sample proportion

                                    p⁻ = 44.4 % = 0.444

Random sample size 'n' = 1049

Given margin of error for 95% confidence level = 3 % = 0.03

Step(ii):-

95% of confidence interval for the proportion is determined by

we know that

Margin of error for 95% confidence level is determined by

Step(iii):-

Now

95% of confidence interval for the proportion is determined by

Given Margin of error

                              M.E = 0.03

Now 95% of confidence interval for the proportion

(0.414 ,0.474)

Conclusion:-

95% of confidence interval for the proportion of registered voters who are in favor of raising income taxes to pay down the national debt.

(0.414 ,0.474)

  b.   the average rate of change of f(x) is less than the average rate of change of g(x).

step-by-step explanation:

since the length of the interval is the same in each case, we only need to compare the change in y-value to see which is greater.

so the change in y-value for function f is (6 )) = 9.

the table tells us

so the change in y-value for function g is (31 -1) = 30.

the change in y-value of f(x) on the interval is less than the change in y-value of g(x) on the same interval, so the average rate of change of f(x) is less than the average rate of change of g(x).

alot

step-by-step explanation:

its a wood chuck that can chuck wood