Use the method of cylindrical shells to find the volume V generated by rotating the region bounded by the given curves about the specified axis. y = 11x − x^2, y = 28; about x = 4

  27π/2

Step-by-step explanation:

The differential of volume is the product of a differential of area and the circumference of the revolution of that area about the given axis. The limits of integration in the x-direction are where y=28 crosses the curve, at x=4 and x=7.

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Check

The parabola's vertex is (5.5, 30.25), so its area above the line y=28 is ...

  A = (2/3)(7 -4)(30.25 -28) = 4.5 . . . square units

The centroid of that area lies on the line x=5.5, a distance of 1.5 from the axis of rotation. So, the volume of revolution is ...

  V = 2π(1.5)(4.5) = 27π/2 . . . matches the above

-7

step-by-step explanation:

x^2 + 18x + 74 = (x + 9)^2 - 81 + 74

= (x + 9)^2 - 7.

so q = -7.