Find the maximum/minimum value of the function y = x2 - (5/3)x + 31/36. A. 1/6

B. 5/6

C. 25/36

D. 10

A

Step-by-step explanation:

Given a parabola in standard form, y = ax² + bx + c ( a ≠ 0 ), then

minimum/ maximum value is the y- coordinate of the vertex.

The x- coordinate of the vertex is

= -

y = x² - x + ← is in standard form

with a = 1 and b = - , thus

= - =

Substitute this value into y

y = ( )² - ( ) +

   = - + =

Since a > 1 then the vertex is a minimum, thus

minimum value = → A