Chords and arcs, find the value of cd

CD = 14

Step-by-step explanation:

Theorem of chords in a circle says,

If two chords are equidistant fro the center in a circle, then the chords will be equal in measure.

Therefore, AB ≅ CD

And a perpendicular drawn from the center bisects the chord in a circle.

AE ≅ EB ≅ 7 units

AB = AE + EB

AB = 2(EB)

Since CD = AB = 2(EB)

CD = 2×7 = 14 units

CD = 14 will be the answer.

this was already solved by me with a different person. if you look it up in the search bar at the top of the page, you will get the answer.

step-by-step explanation:

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.