Factor: (a+3)^2-a(a+3)

Factor (a+3)2−a(a+3)

3a+9

=3(a+3)

3(a+3)

I hope this help :)

the number of possible outcomes that do not show a 1 on the first spinner and show the number 4 on the second spinner is 2.

spinner 1 spinner 2

1                     1

1                     2

1                     3

1                     4

2                   1

2                   2

2                   3

2                   4   = not 1, and 4

3                   1

3                   2

3                   3

3                   4 = not 1, and 4

only 2 outcomes have passed the given condition.

step-by-step explanation:

the answer is 13

step-by-step explanation:

5*5=25

12*12=144

25+144=169

169^2=13