Please answer it now in two minutes

y = -7/5x -8

Step-by-step explanation:

Equation of straight line in point slope form is given by

y = mx +c

where m is the slope of line and

c is y intercept .

Given equation of line u is

y = 5/7 x -6

it is in slope intercept form

thus,

slope = 5/7

we have to find equation of line V which is perpendicular to given line.

we know that product of two perpendicular lines is -1

m1 *m2 = -1

we have m1 = 5/7

thus

5/7*m2 = -1

m2 = -7/5

Thus,

slope of line v is -7/5

let the equation of line V be

y = mx + c

m = -7/5

thus,

equation of line V can be written as

y -7/5 x + c

this line pass passes through point(-10,6)

putting x = -10 and y = 6

we have

6 = -7/5*-10 +c

6 = 14+c

c= 6-14 = -8

Thus,

equation of line in slope intercept form is y = -7/5x -8

hope it you

step-by-step explanation:

sin(7pi/6 - pi/3)  

= sin(7pi/6 - 2pi/6)  

= sin(5pi/6)  

= sin(pi - pi/6)  

= sin(pi/6)  

= 1/2  

sin 7pi/6 - sin pi/3  

= sin (pi + pi/6) - sin pi/3  

= -sin pi/6 - sin pi/3  

= -1/2 - sqrt(3)/2  

= -(1+sqrt(3))2