Complete the square to rewrite y= x2 - 6x + 2 in vertex form. Then state whether the vertex is a maximum or a minimum and give its coordinates.

see explanation

Step-by-step explanation:

Given

y = x² - 6x + 2

The equation of a parabola in vertex form is

y = a(x - h)² + k

where (h, k) are the coordinates of the vertex and a is a multiplier

To complete the square

add/subtract ( half the coefficient of the x- term )² to x² - 6x

y = x² + 2(- 3)x + 9 - 9 + 2

  = (x - 3)² - 7 ← in vertex form

with vertex = (3, - 7 ) and a = 1

Since a > 0 then vertex is a minimum

hello from mrbilldoesmath!

answer:

x - 3

discussion:

x^2 - 9 = (x-3) (x+3)   so

(x^2-9)/ (x + 3) = x-3

you,

mrb