A composite figure is divided into two congruent trapezoids, each with a height of 4 cm. 2 trapezoids. Both trapezoids have base lengths of 10 centimeters and 6 centimeters, and a height of 4 centimeters. Trapezoid area: A = one-half (b 1 + b 2) h What is the area of this composite figure? 32 centimeters squared 40 centimeters squared 64 centimeters squared 80 centimeters squared

48 cm^2

Step-by-step explanation:

Problem:

A composite figure is divided into two congruent trapezoids, each with a height of 4 cm. 2 trapezoids. Both trapezoids have base lengths of 10 cm and 6 cm, and a height of 4 cm. Trapezoid area: A = (1/2)(b1 + b2)h What is the area of this composite figure? 32 cm squared 40 cm squared 64 cm squared 80 cm squared

Solution:

The problem gives you all the information you need.

area of trapezoid = A = (1/2)(b1 + b2)h

b1 = 10 cm

b2 = 6 cm

h = 4 cm

Also, keep in mind the composite figure is made up of two trapezoids, so after we find the area of one trapezoid, we will double it to find the total area.

A = (1/2)(10 cm + 6 cm)(4 cm) = 24 cm^2

The area of 1 trapezoid is 24 cm^2.

The total area = 2 * 24 cm^2 = 48 cm^2

the figures below are made out of circles, semicircles, quarter … find the area and the perimeter of each figure and give your answers as a completely simplified exact value in terms of π (no approximations). remember that we'll also have to cut whatever areas we get in half, since we're only dealing im pretty sure that is the right answer

step-by-step explanation:

-6 is the correct option from the above given options