Which equation is y = 2x2 – 8x + 9 rewritten in vertex form?

y = 2(x - 2)² + 1

Step-by-step explanation:

The equation of a parabola in vertex form is

y = a(x - h)² + k

where (h, k) are the coordinates of the vertex and a is a multiplier

Given

y = 2x² - 8x + 9

Using the method of completing the square

Factor out 2 from the first 2 terms

y = 2(x² - 4x) + 9

add/subtract ( half the coefficient of the x- term )² to x² - 4x

y = 2(x² + 2(- 2)x + 4 - 4) + 9

   = 2(x - 2)² - 8 + 9

   = 2(x - 2)² + 1 ← in vertex form

"image"

step-by-step explanation:

in most of these problems, the notation is that the point with a "prime" is the image of the point without. that is, b' is the image of b.

here, there is no dilation or reflection. there is simply translation (with no direction shown). which figure you call the "preimage" and which one you call the "image" is up to you. as a matter of convention, the naming is as described above.

mathpapa

step-by-step explanation: