Given: ∆ABC is isosceles m∠ACB = 120°, CM = 12 m∠BMC = 60° Find: AB

36

Step-by-step explanation:

As the triangle ABC is isosceles so A and B has the same measures

And, the sum of the angles is 180°.

Therefore 2 times the measure of angle

B plus  120° = 180°,

So, the equation:

2x + 120 = 180

So x = 30

Now we have to apply the law of sin on the triangle BMC as shown below:

Now calculate for BC

BC = 20.7

We use the law of sin again i.e

So AB is 36

.19875994384

step-by-step explanation:

1699/ 8548

(2x + 16) + (x) = 180

step-by-step explanation:

given,

abcd is a quadrilateral inscribed in a circle

angle a is labeled x plus 16, (x + 16)

angle b is labeled x degrees, (x)

angle c is labeled 6x minus 4, (6x – 4)

angle d is labeled 2x plus 16, (2x + 16)

what equation can be used to solve for angle b?

we know that the sum of the opposite angles of a simple quadrilateral inscribed in a circle is 180 degrees.

angle b is opposite angle d

therefore, angle b + angle d = 180

(x) + (2x + 16) = 180 

same as (2x + 16) + (x) = 180