Mathematics, 13.07.2020 21:01 jakalacoles19

The population of a city in 2000 was 500,000 while the population of the suburbs of that city in 2000 was 700,000. Suppose that demographic studies show that each year about 6% of the city's population moves to the suburbs (and 94% stays in the city), while 2% of the suburban population moves to the city (and 98% remains in the suburbs). Compute the population of the city and of the suburbs in the year 2002. For simplicity, ignore other influences on the population such as births, deaths, and migration into and out of the city/suburban region.

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Answer from: yariiixox

The population of the city in 2002 is 442,080 while the population of the suburb is 674,080.

The populations are given as:

$\mathbf{P_c = 500000}$ --- the population of the city in 2000

$\mathbf{P_s = 700000}$ --- the population of the suburbs of the city in 2000

For the city, we have:

94% stays, while 6% moves out

For the suburbs, we have:

98% stays, while 2% moves out

Population is calculated using:

$\mathbf{P =P_o r^t}$

Where:

Po represents the initial populationr represents ratet represents time

The population of the city is:

Population = Population that stays in the city in 2 years + Population that enters from the suburbs in 2 years

So, we have:

$\mathbf{P = 500000 \times (94\%)^2 + 700000 \times (2\%)^2}$

$\mathbf{P = 442080}$

The population of the suburb is:

Population = Population that stays in the suburb in 2 years + Population that enters from the city in 2 years

So, we have:

$\mathbf{P = 700000 \times (98\%)^2+ 500000 \times (6\%)^2 }$

$\mathbf{P = 674080}$

Hence, the population of the city in 2002 is 442,080 while the population of the suburb is 674,080.

Read more about population at:

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Answer from: fortwill05

The population of the city in 2002 is 469,280 while the population of the suburb is 730,720.

Step-by-step explanation:

6% of the city's population moves to the suburbs (and 94% stays in the city).2% of the suburban population moves to the city (and 98% remains in the suburbs).

The migration matrix is given as:

$A= \left \begin{array}{cc} \\ C \\S \end{array} \right\left[ \begin{array}{cc} C&S\\ 0.94&0.06 \\0.02&0.98 \end{array} \right]$

The population in the year 2000 (initial state) is given as:

$\left[ \begin{array}{cc} C&S\\ 500,000&700,000 \end{array} \right]$

Therefore, the population of the city and the suburb in 2002 (two years after) is:

$S_0A^2=\left \begin{array}{cc} [500,000&700,000]\\& \end{array} \right\left \begin{array}{cc} \end{array} \right\left[ \begin{array}{cc} 0.94&0.06 \\0.02&0.98 \end{array} \right]^2$

$A^{2} = \left[ \begin{array}{cc} 0.8848 & 0.1152 \\\\ 0.0384 & 0.9616 \end{array} \right]$

Therefore:

$S_0A^2=\left \begin{array}{cc} [500,000&700,000]\\& \end{array} \right\left \begin{array}{cc} \end{array} \right \left[ \begin{array}{cc} 0.8848 & 0.1152 \\ 0.0384 & 0.9616 \end{array} \right]\\\\=\left[ \begin{array}{cc} 500,000*0.8848+700,000*0.0384& 500,000*0.1152 +700,000*0.9616 \end{array} \right]\\\\=\left[ \begin{array}{cc} 469280& 730720 \end{array} \right]$

Therefore, the population of the city in 2002 is 469,280 while the population of the suburb is 730,720.

Answer from: Quest

gmt is 4 hrs ahead of edt so just add four hours to 1: 14: 20 (minutes and seconds stay the same)

gmt is 5: 14: 20

hope this !

~just a girl in love with shawn mendes

Answer from: Quest

Yes. there is a constant ratio of number of calories to gram of protein.12/3=24/4=32/8=44/11=4

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