I NEED HELP PLEASE, THANKS! :) A projectile is fired from ground level with an initial velocity of 35 m/s at an angle of 35° with the horizontal. How long will it take for the projectile to reach the ground? (Show work)

  4.097 s

Step-by-step explanation:

The formula for ballistic motion usually used is ...

  h(t) = -4.9t² +v₀t +s₀

where v₀ and s₀ are the initial vertical velocity and height, respectively. Here, we have v₀ = (35 m/s)sin(35°) and s₀ = 0. We want to solve for h(t) = 0.

  0 = -4.9t² +35sin(35°)t = t(-4.9t +35sin(35°))

This is true for t=0 and for ...

  t = 35sin(35°)/4.9 ≈ 4.09697 . . . seconds

It will take about 4.097 seconds for the projectile to reach the ground.

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Comment on the graph

Desmos has a setting option for angles in degrees. That is what we used here.

cosine

step-by-step explanation:

check above link.

graphically?   well, you graph them both, the solutions is where they both intersect each other, since there are two solutions, meaning they will meet twice, or namely the linear will run into the quadratic curve twice, and where they meet, those x,y coordinates are the solutions to the system.