Please just a quick question can, can you help me. The length of a rectangle is 8cm longer than its breadth, If the perimeter of the rectangle is 80 cm, find its length and breadth * choose one of the options 1.length = 16cm and breadth = 64cm 2.length = 16cm and breadth = 22cm 3.length = 24cm and breadth = 64cm 4.length = 24cm and breadth = 16cm

Let's call the width x and the length x + 8. Perimeter can be calculated by multiplying the sum of the length and width by 2 so we can write:

2(x + x + 8) = 80

2(2x + 8) = 80

2x + 8 = 40

2x = 32

x = 16

This means that the length is 16 cm and the width is 24 cm.

sec ф = 5/3 (quadrant 4)

let x = base

y = perp

z = hypotenuse

sec ф = hypotenuse/base = 5/3

⇒ z = 5 and x = 3

finding y:

z² = x² + y²

5² = 3² + y²

y² = 25-9

y² = 16

y = 4

now finding all other geometric functions of theta:

sin ф = y/z = 4/5

sin ф = -4/5 (sin is negative in the 4th quadrant)

cos ф = x/z = 3/5

cos ф = 3/5 (cos is positive in 4th quadrant)

tan ф = y/x = 4/3

tan ф = -4/3 (tan is negative in 4th quadrant)

cosec ф = z/y = 5/4

cosec ф = -5/4 (cosec is negative in the 4th quadrant)

cot ф = x/y = 3/4

tan ф = -3/4 (tan is negative in 4th quadrant)

answer: the answer is 127 degrees