In the sequence 2001, 2002, 2003, ... , each term after the third is found by subtracting the previous term from the sum of the two terms that precede that term. For example, the fourth term is 2001+2002−2003=2000. What is the 2004th term in this sequence?

The answer is 0.

Step-by-step explanation:

Let's call the answer a.

We want to find a(2004)

That's an even term. We look at the even terms:

2   2002

 4   2000

6   1998

8   1996

10   1994

12   1992

We see that the pattern for the even terms is  

"if you add n and a(n), the sum is always 2004."

That is n + a(n) = 2004, or,

           a(n) = 2004-n when n is even

So when n = 2004, a(2004) = 2004-2004 = 0

0

what? that isnt a question

step-by-step explanation:

6^2 or 36

step-by-step explanation:

6000n

6×1000n

6×10^3 n

so we need 6n need to be a perfect cube

so n has to be 6^2 so that 6n is 6^3

what i'm saying is if you let n be 6^2 you have 6^3×10^3 or 60^3 which is a perfect cube