Image point B'(4, -8) was transformed using the translation (x-2, y + 3). What were the coordinates of B? (2, -5)
(6,-5)
(2,-11)
(6.-11)
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B(6 , -11)

Step-by-step explanation:

(x-2 , y+3)  = (4 , -8)

Compare the x & y co ordinates

x - 2 = 4   ; y + 3 = -8

x = 4 +2  ; y = -8 - 3

x = 6      ; y = -11

B(6 , -11)

< xcy ≅ < xby

step-by-step explanation:

in δcax and δbax,

so, δcax ≅ δbax (side-angle-side or sas)

since δcax ≅ δbax, we can conclude < acx ≅ < abx

in δacy and δaby,

so, δacy ≅ δaby (side-angle-side or sas)

since δacy ≅ δaby, we can conclude < acy ≅ < aby

now,

< acy ≅ < aby

=> < acx + < xcy ≅ < abx + < xby

=> < acx + < xcy ≅ < acx + < xby   (since < acx ≅ < abx already proved above)

subtracting < acx from both sides, we get

< acx + < xcy -< acx ≅ < acx + < xby -< acx

cancelling out < acx and -< acx from both sides, we get

< xcy ≅ < xby (proved)