A quadrilateral has vertices A(4, 5), B(7, 7), C(6, 8), and D(4, 7). The image of the quadrilateral has vertices A"(–6, 0), B"(–9, –2), C"(–8, –3), and D"(–6, –2). Which transformations may have taken place? T(–2, 5) circle sign ry = x T(--2, 5) circle R0, 180degree ry=x circle T(-2,5) R0,180degree circleT(-2,5)

the y will be in still but your answer will be y x 3

step-by-step explanation:

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i believe that the slope of the line is -5

step-by-step explanation:

the polynomial is a perfect square trinomial of the form a^2-2ab+b^2:

option a. true

step-by-step explanation:

9x^2-12x+4

comparing with the form a^2-2ab+b^2

1.) a^2=9x^2

solving for a: square root both sides of the equation:

sqrt(a^2)=sqrt(9x^2)

a=sqrt(9) sqrt(x^2)

a=3x

2.) b^2=4

solving for b: square root both sides of the equation:

sqrt(b^2)=sqrt(4)

b=2

to be a perfet square trinomial 2ab must be equal to 12x. let's check:

2ab = 2 (3x) (2)

2ab = 12x

correct