In AABC, AB = 3 and AC = 9. Find m28 to the nearest degree.
52
58
72
18

72°

Step-by-step explanation:

==>Given:

∆ABC

AB = Opposite side length = 9

AC = Adjacent side length = 3

==>Required:

The measure of angle B

==>Solution:

Since ∆ABC is a right angled triangle, and we are given two sides (opposite and adjacent sides), to find m<B, we'd use the trigonometry formula tan B = Opposite/Adjacent.

Thus,

tan B = 9/3

tan B = 3

B = tan^-1(3) = 71.5650512°

<B to the nearest degree ≈ 72°

24

step-by-step explanation:

step-by-step explanation:

we can use this expression to calculate the energy gain as a particle moves with a field or the energy loss as it moves against it. (note that it is also used to define the electron-volt, a unit of energy equal to that gained by an electron as it falls through a pd of 1 v, i.e. w = 1 ev = 1.6 10-19 c 1 v = 1.6 10-19j).in fact this expression is really nothing more than the statement that potential is the potential energy per unit charge. in this case, v= w/qis simply stating that the change in potential energy(or work done) per unit charge is equal to the change in potential (or potential difference), v.student questions: uniform electric fields2electron beamcathode+5 kvanode0 v