Find the indicated probability. Find the probability that 3 randomly selected people all have the same birthday. Ignore leap years. Round to eight decimal places

P = 0.00000751

the probability that 3 randomly selected people all have the same birthday is 0.00000751

Step-by-step explanation:

the probability that 3 randomly selected people all have the same birthday P;

P = P1 × P2 × P3 1

For the first person, since there is no specified date, he can have any of the 365 days of the year as his birthday. the probability P1 is;

P1 = 365/365 = 1

For the second person, he must have the same birthday as the first. The probability P2 is;

P2 = 1/365

The third person must also have the same birthday as the other two. The probability P3 is;

P3 = 1/365

Substituting the values into equation 1;

P = 1 × 1/365 × 1/365

P = 0.0000075060987051

To eight decimal places;

P = 0.00000751

the probability that 3 randomly selected people all have the same birthday is 0.00000751

0 is its x and y coordinate

given hc ∥ gd.¯¯¯¯¯¯which statement is true

step-by-step explanation:

∠cbe and ∠deb are same-side interior angles