Find the area of the triangle with vertices (3, 4), (8, 4), and (-6,-6).

The area is 25 :)

Step-by-step explanation:

This Is An Obtuse scalene triangle.

Sides: a = 17.205   b = 13.454   c = 5

Area: T = 25

Perimeter: p = 35.658

Angle ∠ A = α = 131.987° = 131°59'14″ = 2.304 rad

Angle ∠ B = β = 35.538° = 35°32'16″ = 0.62 rad

Angle ∠ C = γ = 12.475° = 12°28'30″ = 0.218 rad

Height: ha = 2.906

Height: hb = 3.716

Height: hc = 10

Median: ma = 5.385

Median: mb = 10.735

Median: mc = 15.24

Inradius: r = 1.402

Circumradius: R = 11.573

Vertex coordinates: A[3; 4] B[8; 4] C[-6; -6]

Centroid: CG[1.667; 0.667]

Coordinates of the circumscribed circle: U[0; 0]

Coordinates of the inscribed circle: I[1.963; 1.402]

Exterior (or external, outer) angles of the triangle:

∠ A' = α' = 48.013° = 48°46″ = 2.304 rad

∠ B' = β' = 144.462° = 144°27'44″ = 0.62 rad

∠ C' = γ' = 167.525° = 167°31'30″ = 0.218 rad

step-by-step explanation:

i found the koficent of the linear function and i foun c acordind to the strict formula y=kx+c and then i took 2 as an x and replacet it on the formula i found and then foun the y

f(x)=4

step-by-step explanation: