Which statement is true about the local minimum of the graphed function?
Over the interval (-4,-2), the local minimum is .
Over the interval (-2, -1], the local minimum is 25.
Over the interval [-1, 4], the local minimum is 0.
Over the interval (4.7), the local minimum is -7.

D

Step-by-step explanation:

A is wrong because on the point -4, the function is equal to -12 and a states the local minimum on [-4, -2] is equal to zero. Since -12 < 0, A is wrong.

B is wrong because the function never even reaches 25 on the interval [-2, -2]

C is wrong because we can see that 3.9 is zero and the function is decreasing there. fro this we can determine the functions value at x = 4 is less than 0, meaning the minimum value is also less than 0.

Lastly, we can see that the lowest point fro 4 to 7 is at -7, meaning that D is correct.

geometry: triangles

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answers archive

call the larger triangle abc

then the smaller triangle cde is similar to abc (all angles are equal, aaa).  

ab is the side that is 36, and we wish to find de, the side corresponding to ab

area_cde = area_abc - area_cde --> area_abc / area_cde = 2

let x=length of de

ratio of areas = (ratio of sides)^2

+2+=+%2836%2fx%29%5e2+

+2+=+1296%2fx%5e2+

++x%5e2+=+1296%2f2+=+648+

25.45584