15.) In a laboratory, the count of bacteria in a certain experiment was increasing at the rate of 2.5% per
hour. Find the bacteria at the end of two hours if the
count initially was 4,80,000.

PLZ answer it's urgent plz

Step-by-step explanation:

given,

initial count of bacteria(P)=4,80,000 ,

increasing rate of bacteria(R)=2.5%,

time(T)= 2 hours

amount(A)=p(1+R/100)^T

A=480000(1+2.5/100)^2

A=480000*(1681/1600)

A=504300

therefore, the bacteria at the end of 2 hours is 504300(approx)

itchkirdcbn

Step-by-step explanation:

86rfbbcgui6g

damm bro the struggle

step-by-step explanation:

hi there!

first we need to find out how much they are adding to each number to make the next number.

ex: 4 + 4 = 8, 8 + 8 = 16, and so on.

so continuing with 32,

32 + 32 = 64

64 + 64 = 128

128 + 128 = 256

256 + 256 = 512

4, 8, 16, 32, 64, 128, 256, 512

the 8th term of the sequence will be 512

hope this ! ~