The sum of digits in two-digit number is 13. If the place values of the digits are reversed, the new number is 27 more than the original number. Find the original number.

58

Step-by-step explanation:

The sum of the two digit number is 13. On reversing its digits the new number is 27 more than the original number find the number?

Let's set up a system with two variables: x = tens place of our answer, y = units place of our answer.

Digit sum of a two digit number is 6:

x+y=13

Reverse the digits and you get 27 more than the original value:

10y+x=10x+y+27

Now let's solve:

y=13-x

10(13-x)+x=10x+(13-x)+27

130-10x+x=130x-10x + 27

130-9x=9x+40

-90=18x

x=5

y=13-5

y=8

So our original number was 58. Sum of digits is 13. Swap the order of the digits to make 85, and you have a number 27 more than the original number.

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step-by-step explanation: