Find the zeros of y = x2 - 6x - 4 by completing the square. A. x=-34/13
B. X- 3+ 118
CX13
D. x 316

x = 3 ±

Step-by-step explanation:

Given

y = x² - 6x - 4

To find the zeros let y = 0, that is

x² - 6x - 4 = 0 ( add 4 to both sides )

x² - 6x = 4

To complete the square

add ( half the coefficient of the x- term )² to both sides

x² + 2(- 3)x + 9 = 4 + 9 , that is

(x - 3)² = 13 ( take the square root of both sides )

x - 3 = ± ( add 3 to both sides )

x = 3 ± ← exact solutions

yes because they have the same amount of green and blur marbles.

step-by-step explanation:

the answer would be d.

step-by-step explanation:

move all variables to the left side and all constants to the right side

(x−3)^2+(y−1)^2=16

this is the form of a circle. use this form to determine the center and radius of the circle.

( x − h ) 2 + ( y − k ) 2 = r 2

match the values in this circle to those of the standard form. the variable   r   represents the radius of the circle,   h   represents the x-offset from the origin, and   k   represents the y-offset from origin.

r = 4

h = 3

k = 1

the center of the circle is found at   ( h , k ) .

center:   ( 3 , 1 )

these values represent the important values for graphing and analyzing a circle.

center:   ( 3 , 1 ).

radius:   4