If we express $2x^2 + 6x + 11$ in the form $a(x - h)^2 + k$, then what is $h$? (ignore the $)

h = -

Step-by-step explanation:

The equation of a parabola in vertex form is

y = a(x - h)² + k

where (h, k) are the coordinates of the vertex and a is a multiplier

Given

y = 2x² + 6x + 11 ( factor out 2 from the first 2 terms )

   = 2(x² + 3x) + 11

Using the method of completing the square

add/subtract ( half the coefficient of the x- term )² to x² + 3x

y = 2(x² + 2( )x + - ) + 11

  = 2(x + )² - + 11

  = 2(x + )² + ← in vertex form

with h = -

1/4 because there is 4 grades.

the equation cos(35) =a/25 can be used to find the length of bc what is the length of bc? round to the nearest tenth

step-by-step explanation: