PLEASE HELP WITH GEOMETRY HOMEWORK Information needed to solve:
- Points O and P are the midpoints to the two circles
- The length between O and P is 6
-The two circles are of the same size
-DONT ASSUME ANYTHING OTHER THAN THE INFORMATION GIVEN UNLESS YOU HAVE PROOF AND EVIDENCE TO SHOW IT IS TRUE!!

Shaded area = 6^2 * ( pi/3 - sqrt(3)/2 )

= 6.52 square units (to 2 places of decimals)

Step-by-step explanation:

see solution by same author given in

link

(question 17023327)

Please refer to the diagram for additional letters and measures.

Let

r=radius (OA and PA) of each circle

Area of sector PAOB

= (60+60)/360 * pi * r^2

=pi*(r^2)/3

Area of triangle PAB

= 2* (r cos(60) * r sin(60) /2)

= 2* ((r/2) * r (sqrt(3)/2) /2)

= sqrt(3) * r^2 / 4

= r^2 * sqrt(3)/4

Area of segment AOB

= area of segment PAOB - area of triangle PAB

= r^2 * ( pi/3 - sqrt(3)/4 )

By symmetry, area of shaded area

= area of segment AOB  -  area of triangle AOB

= area of segment AOB  -  area of triangle PAB

= r^2 * ( pi/3 - sqrt(3)/4 )  -   r^2 * ( sqrt(3)/4)

= r^2 * ( pi/3 - 2*sqrt(3)/4 )

= r^2 * ( pi/3 - sqrt(3)/2 )

Since r = b, we substitute

Shaded area

= b^2 * ( pi/3 - sqrt(3)/2 )

Substitute b=6

area

= 6^2 * ( pi/3 - sqrt(3)/2 )

= 6.522197 square units

answer: the area of the parallelogram below is 42 square meters.

- officialprodixy ☕

y=x+9

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step-by-step explanation: