Salt is falling on a Conical pile of 6 cubic meters per minute. The diameter of the cone is twice the height, what is the rate the height is changing when the pile is 9 meters tall.

0.0236 m per minute,

Step-by-step explanation:

Volume of the cone V = 1/3 π r^2 h.

Diameter = 2r = 2h so r = h

and V = 1/3 π h^3

So  the rate of change of volume with height =

dV / dh =  π h^2.

We are given that dV/dt = 6.

So the rate of change of height: dh/dt = dV/dt * dh/dV

= 6 * 1/ π h^2

When  h = 9

dh/dt = 6 / 81π m per minute

= 0.0236 m per minute,

ok then what happened.

step-by-step explanation:

y = | -2(-2) |     →     y = | 4 |     →     y = 4       ⇒   (-2, 4)

y = | -2(-1) |     →     y = | 2 |     →       y =   2       ⇒   (-1, 2)    

y = | -2(0) |     →     y = | 0 |     →       y = 0         ⇒   (0, 0)

y = | -2(1) |   c →     y = | -2 |     →     y =   2         ⇒   (1, 2)    

y = | -2(2) |     →     y = | - 4 |     →     y =   4         ⇒   (2, 4)