Identify an equation in point-form for the line perpendicular to y=-1/3x-6 that pass through -1,5

y - 5 = 3(x + 1).

Step-by-step explanation:

y = -1/3x - 6

The slope of this line is -1/3 so the slope of the perpendicular line to it is -1/-1/3

= 3.

Using the point-slope form of a straight line:

y - y1 = m(x - x1)  where m = the slope and (x1, y1) is a point on the line:

Here m = 3 and (x1, y1) is (-1, 5) so we have:

y - 5 = 3(x - (-1))

y - 5 = 3(x + 1).

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step-by-step explanation:

i'm not sure i quite understand, could you provide more information?