Choose one of the theorems about chords of a circle and state it using your own words. Create a problem about chords that uses the theorem that you explained. Choose a problem that a classmate has posted, and explain how to solve it. Note: If you do not see any other responses, explain how to solve the problem that you posted. Please number your responses to the questions as they are shown (1, 2, and 3).

A chord is a straight line joining 2 points on the circumference of a circle.

The line that connects any two points of the circumference of a circle is known as a chord.

Theorem: A radius or diameter that is perpendicular to a chord divides the chord into two equal parts and vice versa.

Converse: The perpendicular bisector of a chord passes through the center of a circle.

Problem: In the given figure the radius of the circle is 5 cms. what is the length of the chord?

Solution:

Given to us,

radius of the circle, r = 5 cms,

RA = 1 cm,

Radius, r = OA = OP = OQ = 5 cms.

Also, OR = OA - OR = 4 cms.

In ΔOPQ,

According to Pythagorus theorum,

OP² = OR² + RP²

5² = 4² + RP²

RP² = 25 -16 = 9

RP = 3,

We know,

A radius or diameter that is perpendicular to a chord divides the chord into two equal parts and vice versa.

A radius (OA) that is perpendicular to a chord divides the chord into two equal parts(RP = RQ).

Therefore, chord = RP + RQ = 3+3 = 6 cms.

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Step-by-step explanation:

1. A given chord on a circle is perpendicular to a radius through its center, and it is at a distance less that the radius of the circle.

2. A circle of center O has a radius of 13 units. If a chord AB of 10 units is drawn at a distance, d, to the center of the circle, determine the value of d.

3. From question 2, the radius = 13 units, length of chord = 10 units and distance of chord to center of the circle is d.

A radius that meet the chord at center C, and divides it into two equal parts.

So that;

AC = CB = 5 units

Applying Pythagoras theorem to ΔOCB,

OC = d, CB = 5 units and OB = 13 units

= +

169 = 25 +

169 - 25 =

144 =

⇒ d =

       = 12 units

Therefore, the chord is at a distance of 12 units to the center of the circle.

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