I will give BRAINLIEST! please explain!

51.33

Step-by-step explanation:

to get that, we must subtract area of segment DQE (its look like a slice of pizza) by the triangle DQE

so first, we find the area of segment DQE

Area of DQE = (58/360) * Area of whole circle

A.DQE = 58/360 * πr²

A.DQE = (58 * 3.14 * 25²)/360 = 316.34

save it then we do the second step to find the area of triangle DQE. Triangle DQE is isosceles triangle with ∠DQE = 58,

area of triangle = ½ * base * height * sin ∅

∆DEQ = ½ * DQ * EQ * sin 58°

∆DEQ = ½ * 25 * 25 * 0.848

So Area of ∆DEQ = 265.02

then finally we can find the area of segment the problem said

A.DQE - ∆DEQ = 316.34 - 265.02= 51.32 (near 51.33)

0.02

step-by-step explanation:

time of 9 192 631 770 periods of the radiation corresponding to the transition between the 2 hyperfine levels of the ground state of the caesium 133 atom at 0 k (but other seconds are sometimes used in astronomy)

step-by-step explanation:

idk the answer i want to say 10 but then it would be equal so try 9 but then yeah so yeah we love edgen